#Java list directory contents code#

To solve this problem we should use the recursion technique. list the files, directories and go to inside the directories. It is a recursive problem, the program needs to do the same thing in the subdirectory which it done in the parent directory i.e. In the subdirectory list all files and sub-sub-directories, and for those also go to those sub-sub-directories. In the previous program, whenever sub-directory encounters then the program just reads the name and displays it, but this time program should go inside the subdirectory. Java program to get the list of all files in directory and subdirectories This Java program get list of files and directories, display name and their count inside a directory only, it doesn’t list the sub directories and their files. If we pass a file “test.java” as input then it displays, If we pass an empty directory then it display message, Java program to get all files and directory import java.io.File It doesn’t display the correct result when we pass “abc.txt” which is a file rather than a directory, or when the passed directory is empty. And it doesn’t show files inside subdirectories.

It doesn’t tell which one is file or directory. It is a very simple Java that displays files and directories in the given directory. Simple Java program to display all files and directory import java.io.File ĭir2 Hello.java input.txt dir1 index.html abc.txt xyz.txt The array will be empty if there are no file system roots.Īssume we have a “TestFile” directory in our current working directory, The hierarchy of “TestFile” directory is, Or null if the set of roots could not be determined. File listRoots() It returns An array of File objects denoting the available file system roots, They return null if abstract path name is not a directory, or if an I/O error occurs. In the above five methods:- The array will be empty if the directory is empty. Matched with given FileFilter as File objects using File array. File listFiles(FileFilter filter) It returns all file and subdirectory names whose name are File listFiles(FilenameFilter filter) It returns all file and subdirectory names whose nameĪre matched with a given filter as File objects using File array. The directory may contain ‘N’ number of files, for calculating the size of the directory summation of the size of all the files is required. The in-built function of ‘fileName.length ()’ is used to find size of file in Bytes. The size of files in Java can be obtained using the File class. File listFiles() It returns all file and subdirectory names as File objects Java Program to Get the Size of a Directory. Matched with given filter as String objects using String array. String list(FilenameFilter filter) It returns all file and subdirectory names whose name are Return Type Method Description String list() It returns all file and subdirectory names as String objects We can also get them through file extension. We can use them in our program to get all files and directories in a particular directory or to get all files in directory and subdirectories. You can change the default current directory via one of the panels in the Launcher configuration wizard.In the java.io.File class, methods list() and listFiles() are given with their overloaded forms to list the files and directory.

#Java list directory contents code#

I wouldn't expect to see any Java source code in the '.' directory.Ĭan anyone explain to me why src isn't the current folder?'Īssuming that you are launching an application in Eclipse, then the current folder defaults to the project directory. The '.classpath' file suggests that you are looking at an Eclipse project directory, and Eclipse projects are normally configured with the Java files in a subdirectory such as './src'. It only returns objects (files, directories, symlinks, etc) that are directly in dir. It doesn't return all objects in the tree beneath dir. You are misunderstanding what dir.listFiles() returns. You can verify what directory '.' actually is by printing out dir.getCanonicalPath(). The '.' pathname actually means the 'current directory' or 'working directory' for the JVM.

The '.' directory is not what you expect it to be. The problem is most likely one of the following: It should list all of the files and directories directly contained by the nominated directory.